Base | Representation |
---|---|
bin | 1001010101011001… |
… | …01101011111011011 |
3 | 110221020200222211011 |
4 | 10222230231133123 |
5 | 40230400043120 |
6 | 2145134114351 |
7 | 235120416364 |
oct | 45254553733 |
9 | 13836628734 |
10 | 5011331035 |
11 | 21418471a7 |
12 | b7a34b9b7 |
13 | 61b2c8249 |
14 | 3577b0b6b |
15 | 1e4e43c5a |
hex | 12ab2d7db |
5011331035 has 16 divisors (see below), whose sum is σ = 6332522400. Its totient is φ = 3796609536.
The previous prime is 5011331033. The next prime is 5011331041. The reversal of 5011331035 is 5301331105.
It is a cyclic number.
It is not a de Polignac number, because 5011331035 - 21 = 5011331033 is a prime.
It is a super-2 number, since 2×50113310352 = 50226877484708342450, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5011330997 and 5011331015.
It is not an unprimeable number, because it can be changed into a prime (5011331033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 284917 + ... + 301993.
It is an arithmetic number, because the mean of its divisors is an integer number (395782650).
Almost surely, 25011331035 is an apocalyptic number.
5011331035 is a deficient number, since it is larger than the sum of its proper divisors (1321191365).
5011331035 is a wasteful number, since it uses less digits than its factorization.
5011331035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20190.
The product of its (nonzero) digits is 675, while the sum is 22.
The square root of 5011331035 is about 70790.7552933291. The cubic root of 5011331035 is about 1711.2666919552.
The spelling of 5011331035 in words is "five billion, eleven million, three hundred thirty-one thousand, thirty-five".
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