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5011553342035 = 57525031331969
BaseRepresentation
bin100100011101101011111…
…0110110101001001010011
3122202002200202202201020001
41020323113312311021103
51124102130123421120
614354135324430431
71025033651356102
oct110732766651123
918662622681201
105011553342035
11166242a235419
1268b3330a8417
132a478382c326
141347bbd36039
158a566b63e0a
hex48ed7db5253

5011553342035 has 8 divisors (see below), whose sum is σ = 6013876517280. Its totient is φ = 4009234335744.

The previous prime is 5011553341853. The next prime is 5011553342039. The reversal of 5011553342035 is 5302433551105.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5011553342035 is a prime.

It is a super-3 number, since 3×50115533420353 (a number of 39 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5011553341985 and 5011553342003.

It is not an unprimeable number, because it can be changed into a prime (5011553342039) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3096531 + ... + 4428499.

It is an arithmetic number, because the mean of its divisors is an integer number (751734564660).

Almost surely, 25011553342035 is an apocalyptic number.

5011553342035 is a deficient number, since it is larger than the sum of its proper divisors (1002323175245).

5011553342035 is a wasteful number, since it uses less digits than its factorization.

5011553342035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2084477.

The product of its (nonzero) digits is 135000, while the sum is 37.

The spelling of 5011553342035 in words is "five trillion, eleven billion, five hundred fifty-three million, three hundred forty-two thousand, thirty-five".

Divisors: 1 5 752503 1331969 3762515 6659845 1002310668407 5011553342035