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50122113 = 316707371
BaseRepresentation
bin1011111100110…
…0110110000001
310111022110121120
42333030312001
5100312401423
64550142453
71146013416
oct277146601
9114273546
1050122113
1126324538
1214951a29
13a4cbb72
14692a10d
154600ee3
hex2fccd81

50122113 has 4 divisors (see below), whose sum is σ = 66829488. Its totient is φ = 33414740.

The previous prime is 50122109. The next prime is 50122141. The reversal of 50122113 is 31122105.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 50122113 - 22 = 50122109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 50122092 and 50122101.

It is not an unprimeable number, because it can be changed into a prime (50122183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8353683 + ... + 8353688.

It is an arithmetic number, because the mean of its divisors is an integer number (16707372).

Almost surely, 250122113 is an apocalyptic number.

It is an amenable number.

50122113 is a deficient number, since it is larger than the sum of its proper divisors (16707375).

50122113 is a wasteful number, since it uses less digits than its factorization.

50122113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16707374.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 50122113 is about 7079.6972392893. The cubic root of 50122113 is about 368.7028181326.

Adding to 50122113 its reverse (31122105), we get a palindrome (81244218).

The spelling of 50122113 in words is "fifty million, one hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 3 16707371 50122113