Base | Representation |
---|---|
bin | 100100011110011101010… |
… | …1110111000011100011001 |
3 | 122202020222101012120100210 |
4 | 1020330322232320130121 |
5 | 1124114024310442102 |
6 | 14355012103521333 |
7 | 1025123033426562 |
oct | 110747256703431 |
9 | 18666871176323 |
10 | 5013212202777 |
11 | 166310065a009 |
12 | 68b716759249 |
13 | 2a498940362c |
14 | 1348d838d169 |
15 | 8a6125dd36c |
hex | 48f3abb8719 |
5013212202777 has 8 divisors (see below), whose sum is σ = 6691166857440. Its totient is φ = 3338699508320.
The previous prime is 5013212202703. The next prime is 5013212202793. The reversal of 5013212202777 is 7772022123105.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5013212202777 - 214 = 5013212186393 is a prime.
It is a super-3 number, since 3×50132122027773 (a number of 39 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (5013212202797) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 860486652 + ... + 860492477.
It is an arithmetic number, because the mean of its divisors is an integer number (836395857180).
Almost surely, 25013212202777 is an apocalyptic number.
It is an amenable number.
5013212202777 is a deficient number, since it is larger than the sum of its proper divisors (1677954654663).
5013212202777 is a wasteful number, since it uses less digits than its factorization.
5013212202777 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1720980103.
The product of its (nonzero) digits is 82320, while the sum is 39.
The spelling of 5013212202777 in words is "five trillion, thirteen billion, two hundred twelve million, two hundred two thousand, seven hundred seventy-seven".
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