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50132540441 = 91155030231
BaseRepresentation
bin101110101100001000…
…011101110000011001
311210101211012220221002
4232230020131300121
51310132412243231
635010334154345
73423221364014
oct565410356031
9153354186832
1050132540441
111a29656a705
1298713529b5
13495c367919
1425d819237b
1514863260cb
hexbac21dc19

50132540441 has 4 divisors (see below), whose sum is σ = 50187571584. Its totient is φ = 50077509300.

The previous prime is 50132540431. The next prime is 50132540443. The reversal of 50132540441 is 14404523105.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 50132540441 - 230 = 49058798617 is a prime.

It is a super-2 number, since 2×501325404412 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (50132540443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27514205 + ... + 27516026.

It is an arithmetic number, because the mean of its divisors is an integer number (12546892896).

Almost surely, 250132540441 is an apocalyptic number.

It is an amenable number.

50132540441 is a deficient number, since it is larger than the sum of its proper divisors (55031143).

50132540441 is an equidigital number, since it uses as much as digits as its factorization.

50132540441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55031142.

The product of its (nonzero) digits is 9600, while the sum is 29.

The spelling of 50132540441 in words is "fifty billion, one hundred thirty-two million, five hundred forty thousand, four hundred forty-one".

Divisors: 1 911 55030231 50132540441