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50133205425403 = 311617200175013
BaseRepresentation
bin10110110011000100010111…
…11001101001110011111011
320120111200120021122222210001
423121202023321221303323
523032340301042103103
6254342513203533431
713363001365023052
oct1331421371516373
9216450507588701
1050133205425403
1114a79411546821
12575819908a277
1321c8705715919
14c546626b1399
155be12e0e401d
hex2d988be69cfb

50133205425403 has 4 divisors (see below), whose sum is σ = 51750405600448. Its totient is φ = 48516005250360.

The previous prime is 50133205425361. The next prime is 50133205425419. The reversal of 50133205425403 is 30452450233105.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 50133205425403 - 221 = 50133203328251 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (50133205425463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 808600087476 + ... + 808600087537.

It is an arithmetic number, because the mean of its divisors is an integer number (12937601400112).

Almost surely, 250133205425403 is an apocalyptic number.

50133205425403 is a deficient number, since it is larger than the sum of its proper divisors (1617200175045).

50133205425403 is a wasteful number, since it uses less digits than its factorization.

50133205425403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1617200175044.

The product of its (nonzero) digits is 216000, while the sum is 37.

Adding to 50133205425403 its reverse (30452450233105), we get a palindrome (80585655658508).

The spelling of 50133205425403 in words is "fifty trillion, one hundred thirty-three billion, two hundred five million, four hundred twenty-five thousand, four hundred three".

Divisors: 1 31 1617200175013 50133205425403