Base | Representation |
---|---|
bin | 10110110011000100010111… |
… | …11001101001110011111011 |
3 | 20120111200120021122222210001 |
4 | 23121202023321221303323 |
5 | 23032340301042103103 |
6 | 254342513203533431 |
7 | 13363001365023052 |
oct | 1331421371516373 |
9 | 216450507588701 |
10 | 50133205425403 |
11 | 14a79411546821 |
12 | 575819908a277 |
13 | 21c8705715919 |
14 | c546626b1399 |
15 | 5be12e0e401d |
hex | 2d988be69cfb |
50133205425403 has 4 divisors (see below), whose sum is σ = 51750405600448. Its totient is φ = 48516005250360.
The previous prime is 50133205425361. The next prime is 50133205425419. The reversal of 50133205425403 is 30452450233105.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 50133205425403 - 221 = 50133203328251 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (50133205425463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 808600087476 + ... + 808600087537.
It is an arithmetic number, because the mean of its divisors is an integer number (12937601400112).
Almost surely, 250133205425403 is an apocalyptic number.
50133205425403 is a deficient number, since it is larger than the sum of its proper divisors (1617200175045).
50133205425403 is a wasteful number, since it uses less digits than its factorization.
50133205425403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1617200175044.
The product of its (nonzero) digits is 216000, while the sum is 37.
Adding to 50133205425403 its reverse (30452450233105), we get a palindrome (80585655658508).
The spelling of 50133205425403 in words is "fifty trillion, one hundred thirty-three billion, two hundred five million, four hundred twenty-five thousand, four hundred three".
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