Base | Representation |
---|---|
bin | 100100011111011101000… |
… | …1010001000110001110011 |
3 | 122202110111100221122220211 |
4 | 1020332322022020301303 |
5 | 1124132414103212003 |
6 | 14400004153244551 |
7 | 1025230023032152 |
oct | 110767212106163 |
9 | 18673440848824 |
10 | 5015350054003 |
11 | 1663aa83a0303 |
12 | 690012703757 |
13 | 2a4c3a2b4c63 |
14 | 134a5c28d599 |
15 | 8a6da13096d |
hex | 48fba288c73 |
5015350054003 has 8 divisors (see below), whose sum is σ = 5177163301760. Its totient is φ = 4853538541440.
The previous prime is 5015350053979. The next prime is 5015350054027. The reversal of 5015350054003 is 3004500535105.
It is an interprime number because it is at equal distance from previous prime (5015350053979) and next prime (5015350054027).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5015350054003 - 217 = 5015349922931 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5015350054063) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8113963 + ... + 8710171.
It is an arithmetic number, because the mean of its divisors is an integer number (647145412720).
Almost surely, 25015350054003 is an apocalyptic number.
5015350054003 is a deficient number, since it is larger than the sum of its proper divisors (161813247757).
5015350054003 is a wasteful number, since it uses less digits than its factorization.
5015350054003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 867597.
The product of its (nonzero) digits is 22500, while the sum is 31.
Adding to 5015350054003 its reverse (3004500535105), we get a palindrome (8019850589108).
The spelling of 5015350054003 in words is "five trillion, fifteen billion, three hundred fifty million, fifty-four thousand, three".
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