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50172580125601 = 139815135884951
BaseRepresentation
bin10110110100001101101101…
…10100001101101110100001
320120122110012101010000012121
423122012312310031232201
523034011421003004401
6254412544244224241
713365564210323263
oct1332066664155641
9216573171100177
1050172580125601
1114a9408753686a
12576394769b081
1321cc33c081aab
14c56519bcbb33
155c0185c61ca1
hex2da1b6d0dba1

50172580125601 has 4 divisors (see below), whose sum is σ = 50172617408704. Its totient is φ = 50172542842500.

The previous prime is 50172580125599. The next prime is 50172580125641. The reversal of 50172580125601 is 10652108527105.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 50172580125601 - 21 = 50172580125599 is a prime.

It is a super-2 number, since 2×501725801256012 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (50172580125641) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16544325 + ... + 19340626.

It is an arithmetic number, because the mean of its divisors is an integer number (12543154352176).

Almost surely, 250172580125601 is an apocalyptic number.

It is an amenable number.

50172580125601 is a deficient number, since it is larger than the sum of its proper divisors (37283103).

50172580125601 is a wasteful number, since it uses less digits than its factorization.

50172580125601 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37283102.

The product of its (nonzero) digits is 168000, while the sum is 43.

The spelling of 50172580125601 in words is "fifty trillion, one hundred seventy-two billion, five hundred eighty million, one hundred twenty-five thousand, six hundred one".

Divisors: 1 1398151 35884951 50172580125601