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50202041 = 71707071
BaseRepresentation
bin1011111110000…
…0010110111001
310111110112020212
42333200112321
5100322431131
64552000505
71146465431
oct277402671
9114415225
1050202041
112637959a
1214990135
13a529366
14694b2c1
154619a2b
hex2fe05b9

50202041 has 4 divisors (see below), whose sum is σ = 50909184. Its totient is φ = 49494900.

The previous prime is 50202013. The next prime is 50202049. The reversal of 50202041 is 14020205.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14020205 = 52804041.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50202041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (50202049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 353465 + ... + 353606.

It is an arithmetic number, because the mean of its divisors is an integer number (12727296).

Almost surely, 250202041 is an apocalyptic number.

It is an amenable number.

50202041 is a deficient number, since it is larger than the sum of its proper divisors (707143).

50202041 is an equidigital number, since it uses as much as digits as its factorization.

50202041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 707142.

The product of its (nonzero) digits is 80, while the sum is 14.

The square root of 50202041 is about 7085.3398648195. The cubic root of 50202041 is about 368.8986999247.

Adding to 50202041 its reverse (14020205), we get a palindrome (64222246).

It can be divided in two parts, 5020204 and 1, that added together give a palindrome (5020205).

The spelling of 50202041 in words is "fifty million, two hundred two thousand, forty-one".

Divisors: 1 71 707071 50202041