Base | Representation |
---|---|
bin | 100100100010001110011… |
… | …1100001011000100001011 |
3 | 122210000212012011100022202 |
4 | 1021010130330023010023 |
5 | 1124232111342230120 |
6 | 14402430542510415 |
7 | 1025530360236542 |
oct | 111043474130413 |
9 | 18700765140282 |
10 | 5021302305035 |
11 | 1666582278635 |
12 | 6911b3b9540b |
13 | 2a56785030a3 |
14 | 1350649cd159 |
15 | 8a937985875 |
hex | 4911cf0b10b |
5021302305035 has 4 divisors (see below), whose sum is σ = 6025562766048. Its totient is φ = 4017041844024.
The previous prime is 5021302305031. The next prime is 5021302305037. The reversal of 5021302305035 is 5305032031205.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5021302305035 - 22 = 5021302305031 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5021302304989 and 5021302305007.
It is not an unprimeable number, because it can be changed into a prime (5021302305031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 502130230499 + ... + 502130230508.
It is an arithmetic number, because the mean of its divisors is an integer number (1506390691512).
Almost surely, 25021302305035 is an apocalyptic number.
5021302305035 is a deficient number, since it is larger than the sum of its proper divisors (1004260461013).
5021302305035 is a wasteful number, since it uses less digits than its factorization.
5021302305035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1004260461012.
The product of its (nonzero) digits is 13500, while the sum is 29.
The spelling of 5021302305035 in words is "five trillion, twenty-one billion, three hundred two million, three hundred five thousand, thirty-five".
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