Base | Representation |
---|---|
bin | 100100100010001110011… |
… | …1111101111010101100011 |
3 | 122210000212020220211220101 |
4 | 1021010130333233111203 |
5 | 1124232112112140120 |
6 | 14402431014523231 |
7 | 1025530401212515 |
oct | 111043477572543 |
9 | 18700766824811 |
10 | 5021303240035 |
11 | 1666582857065 |
12 | 6911b4366517 |
13 | 2a567876c844 |
14 | 135064b93bb5 |
15 | 8a937abc90a |
hex | 4911cfef563 |
5021303240035 has 4 divisors (see below), whose sum is σ = 6025563888048. Its totient is φ = 4017042592024.
The previous prime is 5021303240033. The next prime is 5021303240039. The reversal of 5021303240035 is 5300423031205.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5021303240035 - 21 = 5021303240033 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5021303239985 and 5021303240012.
It is not an unprimeable number, because it can be changed into a prime (5021303240033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 502130323999 + ... + 502130324008.
It is an arithmetic number, because the mean of its divisors is an integer number (1506390972012).
Almost surely, 25021303240035 is an apocalyptic number.
5021303240035 is a deficient number, since it is larger than the sum of its proper divisors (1004260648013).
5021303240035 is a wasteful number, since it uses less digits than its factorization.
5021303240035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1004260648012.
The product of its (nonzero) digits is 10800, while the sum is 28.
The spelling of 5021303240035 in words is "five trillion, twenty-one billion, three hundred three million, two hundred forty thousand, thirty-five".
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