Base | Representation |
---|---|
bin | 100100100100000111001… |
… | …1001101010010000000011 |
3 | 122210102022111220110002001 |
4 | 1021020032121222100003 |
5 | 1124313410424002003 |
6 | 14404340534404431 |
7 | 1026032640426016 |
oct | 111101631522003 |
9 | 18712274813061 |
10 | 5025353344003 |
11 | 1668270a52123 |
12 | 691b44800717 |
13 | 2a5b72884a75 |
14 | 13532aa2b37d |
15 | 8aac343d61d |
hex | 4920e66a403 |
5025353344003 has 12 divisors (see below), whose sum is σ = 5078283172920. Its totient is φ = 4972968996800.
The previous prime is 5025353343977. The next prime is 5025353344049. The reversal of 5025353344003 is 3004433535205.
5025353344003 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5025353344003 - 217 = 5025353212931 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5025353344303) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 19324143 + ... + 19582471.
It is an arithmetic number, because the mean of its divisors is an integer number (423190264410).
Almost surely, 25025353344003 is an apocalyptic number.
5025353344003 is a deficient number, since it is larger than the sum of its proper divisors (52929828917).
5025353344003 is a wasteful number, since it uses less digits than its factorization.
5025353344003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 260438 (or 260337 counting only the distinct ones).
The product of its (nonzero) digits is 324000, while the sum is 37.
Adding to 5025353344003 its reverse (3004433535205), we get a palindrome (8029786879208).
The spelling of 5025353344003 in words is "five trillion, twenty-five billion, three hundred fifty-three million, three hundred forty-four thousand, three".
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