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50255311153 = 353914200427
BaseRepresentation
bin101110110011011100…
…110011000100110001
311210201101020022200111
4232303130303010301
51310410324424103
635030441421321
73426242045065
oct566334630461
9153641208614
1050255311153
111a3498a4103
1298a649a841
13497b921a08
14260a5cdaa5
151491ec786d
hexbb3733131

50255311153 has 4 divisors (see below), whose sum is σ = 50269515120. Its totient is φ = 50241107188.

The previous prime is 50255311123. The next prime is 50255311189. The reversal of 50255311153 is 35111355205.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50255311153 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (50255311123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7096675 + ... + 7103752.

It is an arithmetic number, because the mean of its divisors is an integer number (12567378780).

Almost surely, 250255311153 is an apocalyptic number.

It is an amenable number.

50255311153 is a deficient number, since it is larger than the sum of its proper divisors (14203967).

50255311153 is a wasteful number, since it uses less digits than its factorization.

50255311153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14203966.

The product of its (nonzero) digits is 11250, while the sum is 31.

Adding to 50255311153 its reverse (35111355205), we get a palindrome (85366666358).

The spelling of 50255311153 in words is "fifty billion, two hundred fifty-five million, three hundred eleven thousand, one hundred fifty-three".

Divisors: 1 3539 14200427 50255311153