Base | Representation |
---|---|
bin | 100100100101101001110… |
… | …0001001101000001110011 |
3 | 122210201211222202222100010 |
4 | 1021023103201031001303 |
5 | 1124342144032324021 |
6 | 14410045033030003 |
7 | 1026210615264645 |
oct | 111132341150163 |
9 | 18721758688303 |
10 | 5028660433011 |
11 | 1669708799036 |
12 | 692708255303 |
13 | 2a627ba79977 |
14 | 135561d30895 |
15 | 8ac18941976 |
hex | 492d384d073 |
5028660433011 has 16 divisors (see below), whose sum is σ = 7104501642528. Its totient is φ = 3152919552000.
The previous prime is 5028660433003. The next prime is 5028660433057. The reversal of 5028660433011 is 1103340668205.
It is not a de Polignac number, because 5028660433011 - 23 = 5028660433003 is a prime.
It is a super-2 number, since 2×50286604330112 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (5028660933011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 36154390 + ... + 36293211.
It is an arithmetic number, because the mean of its divisors is an integer number (444031352658).
Almost surely, 25028660433011 is an apocalyptic number.
5028660433011 is a gapful number since it is divisible by the number (51) formed by its first and last digit.
5028660433011 is a deficient number, since it is larger than the sum of its proper divisors (2075841209517).
5028660433011 is a wasteful number, since it uses less digits than its factorization.
5028660433011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 72448982.
The product of its (nonzero) digits is 103680, while the sum is 39.
The spelling of 5028660433011 in words is "five trillion, twenty-eight billion, six hundred sixty million, four hundred thirty-three thousand, eleven".
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