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50302041 = 316767347
BaseRepresentation
bin1011111111100…
…0110001011001
310111122121102120
42333320301121
5100334131131
64554051453
71150363116
oct277706131
9114577376
1050302041
1126437739
1214a19b89
13a562a2a
14697590d
154639496
hex2ff8c59

50302041 has 4 divisors (see below), whose sum is σ = 67069392. Its totient is φ = 33534692.

The previous prime is 50302019. The next prime is 50302051. The reversal of 50302041 is 14020305.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 50302041 - 27 = 50301913 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 50302041.

It is not an unprimeable number, because it can be changed into a prime (50302051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8383671 + ... + 8383676.

It is an arithmetic number, because the mean of its divisors is an integer number (16767348).

Almost surely, 250302041 is an apocalyptic number.

It is an amenable number.

50302041 is a deficient number, since it is larger than the sum of its proper divisors (16767351).

50302041 is a wasteful number, since it uses less digits than its factorization.

50302041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16767350.

The product of its (nonzero) digits is 120, while the sum is 15.

The square root of 50302041 is about 7092.3931786104. The cubic root of 50302041 is about 369.1434801637.

Adding to 50302041 its reverse (14020305), we get a palindrome (64322346).

The spelling of 50302041 in words is "fifty million, three hundred two thousand, forty-one".

Divisors: 1 3 16767347 50302041