503031113113 has 4 divisors (see below), whose sum is σ = 503039105920. Its totient is φ = 503023120308.

The previous prime is 503031113077. The next prime is 503031113129. The reversal of 503031113113 is 311311130305.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 503031113113 - 2²¹ = 503029015961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (503031113173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3901245 + ... + 4028122.

It is an arithmetic number, because the mean of its divisors is an integer number (125759776480).

Almost surely, 2^503031113113 is an apocalyptic number.

It is an amenable number.

503031113113 is a deficient number, since it is larger than the sum of its proper divisors (7992807).

503031113113 is an equidigital number, since it uses as much as digits as its factorization.

503031113113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7992806.

The product of its (nonzero) digits is 405, while the sum is 22.

Adding to 503031113113 its reverse (311311130305), we get a palindrome (814342243418).

The spelling of 503031113113 in words is "five hundred three billion, thirty-one million, one hundred thirteen thousand, one hundred thirteen".