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5031241 = 10348847
BaseRepresentation
bin10011001100010101001001
3100110121120021
4103030111021
52241444431
6255500441
760523225
oct23142511
910417507
105031241
112927056
121827721
131072087
1494d785
15695b11
hex4cc549

5031241 has 4 divisors (see below), whose sum is σ = 5080192. Its totient is φ = 4982292.

The previous prime is 5031217. The next prime is 5031251. The reversal of 5031241 is 1421305.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1421305 = 5284261.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5031241 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5031251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24321 + ... + 24526.

It is an arithmetic number, because the mean of its divisors is an integer number (1270048).

Almost surely, 25031241 is an apocalyptic number.

It is an amenable number.

5031241 is a deficient number, since it is larger than the sum of its proper divisors (48951).

5031241 is a wasteful number, since it uses less digits than its factorization.

5031241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48950.

The product of its (nonzero) digits is 120, while the sum is 16.

The square root of 5031241 is about 2243.0427994133. The cubic root of 5031241 is about 171.3529978725.

Adding to 5031241 its reverse (1421305), we get a palindrome (6452546).

The spelling of 5031241 in words is "five million, thirty-one thousand, two hundred forty-one".

Divisors: 1 103 48847 5031241