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5033354402121 = 317143968584589
BaseRepresentation
bin100100100111110101101…
…0011010001100101001001
3122211011222010022022102220
41021033223103101211021
51124431302211331441
614412142513044253
71026435133334043
oct111175323214511
918734863268386
105033354402121
1116706a7382551
126935b8256689
132a68493a8696
141358894cca93
158ade0a97466
hex493eb4d1949

5033354402121 has 16 divisors (see below), whose sum is σ = 7110850291200. Its totient is φ = 3155988401408.

The previous prime is 5033354401987. The next prime is 5033354402137. The reversal of 5033354402121 is 1212044533305.

It is a cyclic number.

It is not a de Polignac number, because 5033354402121 - 215 = 5033354369353 is a prime.

It is not an unprimeable number, because it can be changed into a prime (5033354402621) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34218906 + ... + 34365683.

It is an arithmetic number, because the mean of its divisors is an integer number (444428143200).

Almost surely, 25033354402121 is an apocalyptic number.

5033354402121 is a gapful number since it is divisible by the number (51) formed by its first and last digit.

It is an amenable number.

5033354402121 is a deficient number, since it is larger than the sum of its proper divisors (2077495889079).

5033354402121 is a wasteful number, since it uses less digits than its factorization.

5033354402121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68586048.

The product of its (nonzero) digits is 43200, while the sum is 33.

Adding to 5033354402121 its reverse (1212044533305), we get a palindrome (6245398935426).

The spelling of 5033354402121 in words is "five trillion, thirty-three billion, three hundred fifty-four million, four hundred two thousand, one hundred twenty-one".

Divisors: 1 3 17 51 1439 4317 24463 73389 68584589 205753767 1165938013 3497814039 98693223571 296079670713 1677784800707 5033354402121