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50334025353 = 316778008451
BaseRepresentation
bin101110111000001001…
…000100011010001001
311210220212100102021020
4232320021010122021
51311041002302403
635042332503053
73431216104413
oct567011043211
9153825312236
1050334025353
111a38a277267
12990891aa89
134992021a71
142616c3d9b3
151498d75453
hexbb8244689

50334025353 has 4 divisors (see below), whose sum is σ = 67112033808. Its totient is φ = 33556016900.

The previous prime is 50334025333. The next prime is 50334025361. The reversal of 50334025353 is 35352043305.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 50334025353 - 218 = 50333763209 is a prime.

It is not an unprimeable number, because it can be changed into a prime (50334025333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8389004223 + ... + 8389004228.

It is an arithmetic number, because the mean of its divisors is an integer number (16778008452).

Almost surely, 250334025353 is an apocalyptic number.

It is an amenable number.

50334025353 is a deficient number, since it is larger than the sum of its proper divisors (16778008455).

50334025353 is a wasteful number, since it uses less digits than its factorization.

50334025353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16778008454.

The product of its (nonzero) digits is 81000, while the sum is 33.

Adding to 50334025353 its reverse (35352043305), we get a palindrome (85686068658).

The spelling of 50334025353 in words is "fifty billion, three hundred thirty-four million, twenty-five thousand, three hundred fifty-three".

Divisors: 1 3 16778008451 50334025353