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5034311205441 = 37234247015003
BaseRepresentation
bin100100101000010010001…
…0101001100001001000001
3122211021102210200221211220
41021100210111030021001
51124440232132033231
614412421452425253
71026500632124100
oct111204425141101
918737383627756
105034311205441
111671048481aa1
12693824778229
132a696c69ccab
1413593a5d4037
158ae49a94896
hex4942454c241

5034311205441 has 12 divisors (see below), whose sum is σ = 7808319420912. Its totient is φ = 2876749260168.

The previous prime is 5034311205433. The next prime is 5034311205457. The reversal of 5034311205441 is 1445021134305.

It is not a de Polignac number, because 5034311205441 - 23 = 5034311205433 is a prime.

It is not an unprimeable number, because it can be changed into a prime (5034311005441) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 17123507355 + ... + 17123507648.

It is an arithmetic number, because the mean of its divisors is an integer number (650693285076).

Almost surely, 25034311205441 is an apocalyptic number.

It is an amenable number.

5034311205441 is a deficient number, since it is larger than the sum of its proper divisors (2774008215471).

5034311205441 is a wasteful number, since it uses less digits than its factorization.

5034311205441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34247015020 (or 34247015013 counting only the distinct ones).

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 5034311205441 its reverse (1445021134305), we get a palindrome (6479332339746).

The spelling of 5034311205441 in words is "five trillion, thirty-four billion, three hundred eleven million, two hundred five thousand, four hundred forty-one".

Divisors: 1 3 7 21 49 147 34247015003 102741045009 239729105021 719187315063 1678103735147 5034311205441