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50343424121 = 232188844527
BaseRepresentation
bin101110111000101100…
…111011000001111001
311210221112000220221202
4232320230323001321
51311100404032441
635043310143545
73431362021154
oct567054730171
9153845026852
1050343424121
111a394606741
12990bab1bb5
134993c62a73
1426181a8c9b
151499ad019b
hexbb8b3b079

50343424121 has 4 divisors (see below), whose sum is σ = 52532268672. Its totient is φ = 48154579572.

The previous prime is 50343424093. The next prime is 50343424123. The reversal of 50343424121 is 12142434305.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50343424121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (50343424123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1094422241 + ... + 1094422286.

It is an arithmetic number, because the mean of its divisors is an integer number (13133067168).

Almost surely, 250343424121 is an apocalyptic number.

It is an amenable number.

50343424121 is a deficient number, since it is larger than the sum of its proper divisors (2188844551).

50343424121 is a wasteful number, since it uses less digits than its factorization.

50343424121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2188844550.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 50343424121 its reverse (12142434305), we get a palindrome (62485858426).

The spelling of 50343424121 in words is "fifty billion, three hundred forty-three million, four hundred twenty-four thousand, one hundred twenty-one".

Divisors: 1 23 2188844527 50343424121