Base | Representation |
---|---|
bin | 100100101000011000001… |
… | …0011101010011111001011 |
3 | 122211021221210210002022220 |
4 | 1021100300103222133023 |
5 | 1124441140101211133 |
6 | 14412453431145123 |
7 | 1026505622020662 |
oct | 111206023523713 |
9 | 18737853702286 |
10 | 5034512132043 |
11 | 1671140938139 |
12 | 69387bb151a3 |
13 | 2a69a21bcc84 |
14 | 135959177dd9 |
15 | 8ae5c5335b3 |
hex | 494304ea7cb |
5034512132043 has 4 divisors (see below), whose sum is σ = 6712682842728. Its totient is φ = 3356341421360.
The previous prime is 5034512131963. The next prime is 5034512132047. The reversal of 5034512132043 is 3402312154305.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5034512132043 - 221 = 5034510034891 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5034512131995 and 5034512132013.
It is not an unprimeable number, because it can be changed into a prime (5034512132047) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 839085355338 + ... + 839085355343.
It is an arithmetic number, because the mean of its divisors is an integer number (1678170710682).
Almost surely, 25034512132043 is an apocalyptic number.
5034512132043 is a deficient number, since it is larger than the sum of its proper divisors (1678170710685).
5034512132043 is a wasteful number, since it uses less digits than its factorization.
5034512132043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1678170710684.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 5034512132043 its reverse (3402312154305), we get a palindrome (8436824286348).
The spelling of 5034512132043 in words is "five trillion, thirty-four billion, five hundred twelve million, one hundred thirty-two thousand, forty-three".
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