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5035353413153 = 731163142358243
BaseRepresentation
bin100100101000110001001…
…1100111001011000100001
3122211101010102210121001112
41021101202130321120201
51124444400433210103
614413113122513105
71026535515546410
oct111214234713041
918741112717045
105035353413153
111671532804088
12693a75805795
132a6aa759784b
141359d8bab477
158aeab311cd8
hex49462739621

5035353413153 has 16 divisors (see below), whose sum is σ = 5976768516096. Its totient is φ = 4151166336720.

The previous prime is 5035353413087. The next prime is 5035353413159. The reversal of 5035353413153 is 3513143535305.

It is a cyclic number.

It is not a de Polignac number, because 5035353413153 - 222 = 5035349218849 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 5035353413153.

It is not an unprimeable number, because it can be changed into a prime (5035353413159) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 71143751 + ... + 71214492.

It is an arithmetic number, because the mean of its divisors is an integer number (373548032256).

Almost surely, 25035353413153 is an apocalyptic number.

It is an amenable number.

5035353413153 is a deficient number, since it is larger than the sum of its proper divisors (941415102943).

5035353413153 is a wasteful number, since it uses less digits than its factorization.

5035353413153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 142358444.

The product of its (nonzero) digits is 607500, while the sum is 41.

Adding to 5035353413153 its reverse (3513143535305), we get a palindrome (8548496948458).

The spelling of 5035353413153 in words is "five trillion, thirty-five billion, three hundred fifty-three million, four hundred thirteen thousand, one hundred fifty-three".

Divisors: 1 7 31 163 217 1141 5053 35371 142358243 996507701 4413105533 23204393609 30891738731 162430755263 719336201879 5035353413153