Base | Representation |
---|---|
bin | 100100101000110010100… |
… | …1111011010101100101001 |
3 | 122211101020200212011222001 |
4 | 1021101211033122230221 |
5 | 1124444444423224431 |
6 | 14413121513531001 |
7 | 1026536624410111 |
oct | 111214517325451 |
9 | 18741220764861 |
10 | 5035400211241 |
11 | 1671557168194 |
12 | 693a89413a61 |
13 | 2a6ab41a171a |
14 | 135a010b0041 |
15 | 8aeb04a7e61 |
hex | 494653dab29 |
5035400211241 has 4 divisors (see below), whose sum is σ = 5254330655232. Its totient is φ = 4816469767252.
The previous prime is 5035400211239. The next prime is 5035400211263. The reversal of 5035400211241 is 1421120045305.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5035400211241 - 21 = 5035400211239 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5035400211271) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 109465221961 + ... + 109465222006.
It is an arithmetic number, because the mean of its divisors is an integer number (1313582663808).
Almost surely, 25035400211241 is an apocalyptic number.
It is an amenable number.
5035400211241 is a deficient number, since it is larger than the sum of its proper divisors (218930443991).
5035400211241 is a wasteful number, since it uses less digits than its factorization.
5035400211241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 218930443990.
The product of its (nonzero) digits is 4800, while the sum is 28.
Adding to 5035400211241 its reverse (1421120045305), we get a palindrome (6456520256546).
The spelling of 5035400211241 in words is "five trillion, thirty-five billion, four hundred million, two hundred eleven thousand, two hundred forty-one".
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