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50401235201 = 79637990319
BaseRepresentation
bin101110111100001001…
…011101000100000001
311211002112211000211212
4232330021131010001
51311210204011301
635053133215505
73432663300452
oct567411350401
9154075730755
1050401235201
111a414201a99
129927331595
1349a2c245c5
142621b37129
15149ebee4bb
hexbbc25d101

50401235201 has 4 divisors (see below), whose sum is σ = 51039225600. Its totient is φ = 49763244804.

The previous prime is 50401235123. The next prime is 50401235221. The reversal of 50401235201 is 10253210405.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50401235201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (50401235221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 318995081 + ... + 318995238.

It is an arithmetic number, because the mean of its divisors is an integer number (12759806400).

Almost surely, 250401235201 is an apocalyptic number.

It is an amenable number.

50401235201 is a deficient number, since it is larger than the sum of its proper divisors (637990399).

50401235201 is an equidigital number, since it uses as much as digits as its factorization.

50401235201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 637990398.

The product of its (nonzero) digits is 1200, while the sum is 23.

Adding to 50401235201 its reverse (10253210405), we get a palindrome (60654445606).

The spelling of 50401235201 in words is "fifty billion, four hundred one million, two hundred thirty-five thousand, two hundred one".

Divisors: 1 79 637990319 50401235201