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50402040121 = 72196981859
BaseRepresentation
bin101110111100001100…
…100001100100111001
311211002121022220222201
4232330030201210321
51311210410240441
635053202350201
73433003162246
oct567414414471
9154077286881
1050402040121
111a414701814
12992765b361
1349a3146aa4
142621ca65cd
15149ed0cc31
hexbbc321939

50402040121 has 4 divisors (see below), whose sum is σ = 50409029200. Its totient is φ = 50395051044.

The previous prime is 50402040077. The next prime is 50402040217. The reversal of 50402040121 is 12104020405.

50402040121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 50402040121 - 221 = 50399942969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (50402040421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3483711 + ... + 3498148.

It is an arithmetic number, because the mean of its divisors is an integer number (12602257300).

Almost surely, 250402040121 is an apocalyptic number.

It is an amenable number.

50402040121 is a deficient number, since it is larger than the sum of its proper divisors (6989079).

50402040121 is an equidigital number, since it uses as much as digits as its factorization.

50402040121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6989078.

The product of its (nonzero) digits is 320, while the sum is 19.

Adding to 50402040121 its reverse (12104020405), we get a palindrome (62506060526).

The spelling of 50402040121 in words is "fifty billion, four hundred two million, forty thousand, one hundred twenty-one".

Divisors: 1 7219 6981859 50402040121