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50402167161 = 316800722387
BaseRepresentation
bin101110111100001101…
…000000100101111001
311211002121120101020220
4232330031000211321
51311210423322121
635053205210253
73433004231523
oct567415004571
9154077511226
1050402167161
111a414789205
129927700989
1349a318c868
142621cdaa13
15149ed356c6
hexbbc340979

50402167161 has 4 divisors (see below), whose sum is σ = 67202889552. Its totient is φ = 33601444772.

The previous prime is 50402167157. The next prime is 50402167163. The reversal of 50402167161 is 16176120405.

50402167161 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 50402167161 - 22 = 50402167157 is a prime.

It is not an unprimeable number, because it can be changed into a prime (50402167163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8400361191 + ... + 8400361196.

It is an arithmetic number, because the mean of its divisors is an integer number (16800722388).

Almost surely, 250402167161 is an apocalyptic number.

It is an amenable number.

50402167161 is a deficient number, since it is larger than the sum of its proper divisors (16800722391).

50402167161 is a wasteful number, since it uses less digits than its factorization.

50402167161 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16800722390.

The product of its (nonzero) digits is 10080, while the sum is 33.

Adding to 50402167161 its reverse (16176120405), we get a palindrome (66578287566).

The spelling of 50402167161 in words is "fifty billion, four hundred two million, one hundred sixty-seven thousand, one hundred sixty-one".

Divisors: 1 3 16800722387 50402167161