Base | Representation |
---|---|
bin | 100100101011000101000… |
… | …1011111110100111000011 |
3 | 122211211221012222001101111 |
4 | 1021112022023332213003 |
5 | 1130040031122042201 |
6 | 14415253323344151 |
7 | 1030102463616433 |
oct | 111261213764703 |
9 | 18754835861344 |
10 | 5040315034051 |
11 | 1673649488320 |
12 | 694a1b382057 |
13 | 2a73b84a95bb |
14 | 135d49b1c2c3 |
15 | 8b19bbd6b51 |
hex | 4958a2fe9c3 |
5040315034051 has 16 divisors (see below), whose sum is σ = 5522891155200. Its totient is φ = 4561802431200.
The previous prime is 5040315034043. The next prime is 5040315034063. The reversal of 5040315034051 is 1504305130405.
5040315034051 is digitally balanced in base 12, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 5040315034051 - 23 = 5040315034043 is a prime.
It is a Duffinian number.
5040315034051 is strictly pandigital in base 12.
It is not an unprimeable number, because it can be changed into a prime (5040315034021) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 45616810 + ... + 45727168.
It is an arithmetic number, because the mean of its divisors is an integer number (345180697200).
Almost surely, 25040315034051 is an apocalyptic number.
5040315034051 is a deficient number, since it is larger than the sum of its proper divisors (482576121149).
5040315034051 is a wasteful number, since it uses less digits than its factorization.
5040315034051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 128730.
The product of its (nonzero) digits is 18000, while the sum is 31.
The spelling of 5040315034051 in words is "five trillion, forty billion, three hundred fifteen million, thirty-four thousand, fifty-one".
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