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5040341401555 = 51008068280311
BaseRepresentation
bin100100101011000101111…
…0000100011111111010011
3122211212000001120122210201
41021112023300203333103
51130040104344322210
614415300104440031
71030103234005555
oct111261360437723
918755001518721
105040341401555
111673662357649
12694a28179017
132a73c0aac085
14135d4d4234d5
158b19e19453a
hex4958bc23fd3

5040341401555 has 4 divisors (see below), whose sum is σ = 6048409681872. Its totient is φ = 4032273121240.

The previous prime is 5040341401553. The next prime is 5040341401583. The reversal of 5040341401555 is 5551041430405.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 5040341401555 - 21 = 5040341401553 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5040341401553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 504034140151 + ... + 504034140160.

It is an arithmetic number, because the mean of its divisors is an integer number (1512102420468).

Almost surely, 25040341401555 is an apocalyptic number.

5040341401555 is a deficient number, since it is larger than the sum of its proper divisors (1008068280317).

5040341401555 is a wasteful number, since it uses less digits than its factorization.

5040341401555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1008068280316.

The product of its (nonzero) digits is 120000, while the sum is 37.

The spelling of 5040341401555 in words is "five trillion, forty billion, three hundred forty-one million, four hundred one thousand, five hundred fifty-five".

Divisors: 1 5 1008068280311 5040341401555