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5041254050003 = 70127799258697
BaseRepresentation
bin100100101011100001000…
…1010000010100011010011
3122211221100122220000010002
41021113002022002203103
51130043442014100003
614415530430000215
71030134655254323
oct111270212024323
918757318800102
105041254050003
111673a90538966
1269504194606b
132a7507bb3942
14135dd8713283
158b20436da88
hex495c22828d3

5041254050003 has 8 divisors (see below), whose sum is σ = 5048646688800. Its totient is φ = 5033861985600.

The previous prime is 5041254049969. The next prime is 5041254050017. The reversal of 5041254050003 is 3000504521405.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5041254050003 - 214 = 5041254033619 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5041254050093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19357751 + ... + 19616447.

It is an arithmetic number, because the mean of its divisors is an integer number (631080836100).

Almost surely, 25041254050003 is an apocalyptic number.

5041254050003 is a deficient number, since it is larger than the sum of its proper divisors (7392638797).

5041254050003 is a wasteful number, since it uses less digits than its factorization.

5041254050003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 287197.

The product of its (nonzero) digits is 12000, while the sum is 29.

Adding to 5041254050003 its reverse (3000504521405), we get a palindrome (8041758571408).

The spelling of 5041254050003 in words is "five trillion, forty-one billion, two hundred fifty-four million, fifty thousand, three".

Divisors: 1 701 27799 258697 19487099 181346597 7191517903 5041254050003