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504212113 = 1814327791
BaseRepresentation
bin11110000011011…
…010101010010001
31022010202121222201
4132003122222101
52013034241423
6122011003201
715331506106
oct3603325221
91263677881
10504212113
11239684029
12120a39501
13805cb382
144ad70aad
152e3eb2ad
hex1e0daa91

504212113 has 4 divisors (see below), whose sum is σ = 504258048. Its totient is φ = 504166180.

The previous prime is 504212087. The next prime is 504212131. The reversal of 504212113 is 311212405.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-504212113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (504212413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4248 + ... + 32038.

It is an arithmetic number, because the mean of its divisors is an integer number (126064512).

Almost surely, 2504212113 is an apocalyptic number.

It is an amenable number.

504212113 is a deficient number, since it is larger than the sum of its proper divisors (45935).

504212113 is a wasteful number, since it uses less digits than its factorization.

504212113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45934.

The product of its (nonzero) digits is 240, while the sum is 19.

The square root of 504212113 is about 22454.6679556835. The cubic root of 504212113 is about 795.9230674240.

Adding to 504212113 its reverse (311212405), we get a palindrome (815424518).

The spelling of 504212113 in words is "five hundred four million, two hundred twelve thousand, one hundred thirteen".

Divisors: 1 18143 27791 504212113