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5044022445153 = 31681340815051
BaseRepresentation
bin100100101100110011100…
…1010101000010001100001
3122212012111121010001022210
41021121213022220101201
51130120124221221103
614421105242152333
71030263402241236
oct111314712502141
918765447101283
105044022445153
11167518119a13a
12695694ab26a9
132a78595c6593
141361bc26b78d
158b317413e03
hex496672a8461

5044022445153 has 4 divisors (see below), whose sum is σ = 6725363260208. Its totient is φ = 3362681630100.

The previous prime is 5044022445109. The next prime is 5044022445157. The reversal of 5044022445153 is 3515442204405.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 5044022445153 - 29 = 5044022444641 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5044022445157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 840670407523 + ... + 840670407528.

It is an arithmetic number, because the mean of its divisors is an integer number (1681340815052).

Almost surely, 25044022445153 is an apocalyptic number.

It is an amenable number.

5044022445153 is a deficient number, since it is larger than the sum of its proper divisors (1681340815055).

5044022445153 is a wasteful number, since it uses less digits than its factorization.

5044022445153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1681340815054.

The product of its (nonzero) digits is 384000, while the sum is 39.

Adding to 5044022445153 its reverse (3515442204405), we get a palindrome (8559464649558).

The spelling of 5044022445153 in words is "five trillion, forty-four billion, twenty-two million, four hundred forty-five thousand, one hundred fifty-three".

Divisors: 1 3 1681340815051 5044022445153