Base | Representation |
---|---|
bin | 111001010110010010010001… |
… | …1100110111000001100100001 |
3 | 2110011002000100122120112201122 |
4 | 1302230210203212320030201 |
5 | 1012104222023100421423 |
6 | 4544504344532342025 |
7 | 211152413454556424 |
oct | 16254444346701441 |
9 | 2404060318515648 |
10 | 504440211342113 |
11 | 13680398a634282 |
12 | 486aba86174915 |
13 | 1886167a8a89c7 |
14 | 8c7d0722219bb |
15 | 3d4b9aa5d38c8 |
hex | 1cac9239b8321 |
504440211342113 has 16 divisors (see below), whose sum is σ = 526587514214400. Its totient is φ = 482310855797760.
The previous prime is 504440211342083. The next prime is 504440211342121. The reversal of 504440211342113 is 311243112044405.
It is a cyclic number.
It is not a de Polignac number, because 504440211342113 - 216 = 504440211276577 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (504440211342173) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1120232753 + ... + 1120682961.
It is an arithmetic number, because the mean of its divisors is an integer number (32911719638400).
Almost surely, 2504440211342113 is an apocalyptic number.
It is an amenable number.
504440211342113 is a deficient number, since it is larger than the sum of its proper divisors (22147302872287).
504440211342113 is a wasteful number, since it uses less digits than its factorization.
504440211342113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 470032.
The product of its (nonzero) digits is 46080, while the sum is 35.
Adding to 504440211342113 its reverse (311243112044405), we get a palindrome (815683323386518).
The spelling of 504440211342113 in words is "five hundred four trillion, four hundred forty billion, two hundred eleven million, three hundred forty-two thousand, one hundred thirteen".
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