Base | Representation |
---|---|
bin | 10110111100000111101011… |
… | …00010101111110110101011 |
3 | 20121121102100002220021100212 |
4 | 23132003311202233312223 |
5 | 23102434223123413201 |
6 | 255141430324051335 |
7 | 13424321453435522 |
oct | 1336036542576653 |
9 | 217542302807325 |
10 | 50444215451051 |
11 | 150892a95a9274 |
12 | 57a8515833b4b |
13 | 221bb3b56c2b6 |
14 | c65727b734b9 |
15 | 5c7283172abb |
hex | 2de0f58afdab |
50444215451051 has 4 divisors (see below), whose sum is σ = 50444618482104. Its totient is φ = 50443812420000.
The previous prime is 50444215451027. The next prime is 50444215451057. The reversal of 50444215451051 is 15015451244405.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50444215451051 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (50444215451057) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 201327725 + ... + 201578126.
It is an arithmetic number, because the mean of its divisors is an integer number (12611154620526).
Almost surely, 250444215451051 is an apocalyptic number.
50444215451051 is a deficient number, since it is larger than the sum of its proper divisors (403031053).
50444215451051 is a wasteful number, since it uses less digits than its factorization.
50444215451051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 403031052.
The product of its (nonzero) digits is 320000, while the sum is 41.
Adding to 50444215451051 its reverse (15015451244405), we get a palindrome (65459666695456).
The spelling of 50444215451051 in words is "fifty trillion, four hundred forty-four billion, two hundred fifteen million, four hundred fifty-one thousand, fifty-one".
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