Base | Representation |
---|---|
bin | 100100110001000110011… |
… | …1000010100010001011001 |
3 | 122220002022100012010210110 |
4 | 1021202030320110101121 |
5 | 1130243021222112213 |
6 | 14425232340034533 |
7 | 1031041060521036 |
oct | 111421470242131 |
9 | 18802270163713 |
10 | 5053245113433 |
11 | 1679084146340 |
12 | 697429692a49 |
13 | 2a869923994a |
14 | 13681508638d |
15 | 8b6a6e265c3 |
hex | 4988ce14459 |
5053245113433 has 16 divisors (see below), whose sum is σ = 7350214392576. Its totient is φ = 3062556261840.
The previous prime is 5053245113431. The next prime is 5053245113453. The reversal of 5053245113433 is 3343115423505.
It is not a de Polignac number, because 5053245113433 - 21 = 5053245113431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5053245113391 and 5053245113400.
It is not an unprimeable number, because it can be changed into a prime (5053245113431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8972910 + ... + 9519432.
It is an arithmetic number, because the mean of its divisors is an integer number (459388399536).
Almost surely, 25053245113433 is an apocalyptic number.
It is an amenable number.
5053245113433 is a deficient number, since it is larger than the sum of its proper divisors (2296969279143).
5053245113433 is a wasteful number, since it uses less digits than its factorization.
5053245113433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 826724.
The product of its (nonzero) digits is 324000, while the sum is 39.
The spelling of 5053245113433 in words is "five trillion, fifty-three billion, two hundred forty-five million, one hundred thirteen thousand, four hundred thirty-three".
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