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5053252031331 = 37317759088483
BaseRepresentation
bin100100110001000110101…
…0010101101001101100011
3122220002022211012121100220
41021202031102231031203
51130243030010000311
614425233144214123
71031041203362610
oct111421522551543
918802284177326
105053252031331
111679088040909
1269742ba6a343
132a869a7bc68a
14136815d67507
158b6a7841206
hex4988d4ad363

5053252031331 has 16 divisors (see below), whose sum is σ = 7724484413184. Its totient is φ = 2878463523744.

The previous prime is 5053252031329. The next prime is 5053252031339. The reversal of 5053252031331 is 1331302523505.

It is not a de Polignac number, because 5053252031331 - 21 = 5053252031329 is a prime.

It is a super-2 number, since 2×50532520313312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5053252031292 and 5053252031301.

It is not an unprimeable number, because it can be changed into a prime (5053252031339) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 379537585 + ... + 379550898.

It is an arithmetic number, because the mean of its divisors is an integer number (482780275824).

Almost surely, 25053252031331 is an apocalyptic number.

5053252031331 is a deficient number, since it is larger than the sum of its proper divisors (2671232381853).

5053252031331 is a wasteful number, since it uses less digits than its factorization.

5053252031331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 759088810.

The product of its (nonzero) digits is 40500, while the sum is 33.

Adding to 5053252031331 its reverse (1331302523505), we get a palindrome (6384554554836).

The spelling of 5053252031331 in words is "five trillion, fifty-three billion, two hundred fifty-two million, thirty-one thousand, three hundred thirty-one".

Divisors: 1 3 7 21 317 951 2219 6657 759088483 2277265449 5313619381 15940858143 240631049111 721893147333 1684417343777 5053252031331