Base | Representation |
---|---|
bin | 111001100100000111100011… |
… | …1110001011010100001110011 |
3 | 2110101210202111122122022222021 |
4 | 1303020033013301122201303 |
5 | 1012331344031311044220 |
6 | 4552522000105252311 |
7 | 211436645312153143 |
oct | 16310170761324163 |
9 | 2411722448568867 |
10 | 506341341112435 |
11 | 13737717a848144 |
12 | 48958416794097 |
13 | 1896ba2570589a |
14 | 8d070a1adc923 |
15 | 3d8117863d4aa |
hex | 1cc83c7c5a873 |
506341341112435 has 4 divisors (see below), whose sum is σ = 607609609334928. Its totient is φ = 405073072889944.
The previous prime is 506341341112427. The next prime is 506341341112469. The reversal of 506341341112435 is 534211143143605.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 506341341112435 - 23 = 506341341112427 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 506341341112391 and 506341341112400.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50634134111239 + ... + 50634134111248.
It is an arithmetic number, because the mean of its divisors is an integer number (151902402333732).
Almost surely, 2506341341112435 is an apocalyptic number.
506341341112435 is a deficient number, since it is larger than the sum of its proper divisors (101268268222493).
506341341112435 is a wasteful number, since it uses less digits than its factorization.
506341341112435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 101268268222492.
The product of its (nonzero) digits is 518400, while the sum is 43.
The spelling of 506341341112435 in words is "five hundred six trillion, three hundred forty-one billion, three hundred forty-one million, one hundred twelve thousand, four hundred thirty-five".
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