Base | Representation |
---|---|
bin | 1110110000011101110… |
… | …01001110111000101011 |
3 | 1210110210121100221001122 |
4 | 13120032321032320223 |
5 | 31301422320301011 |
6 | 1024534402205455 |
7 | 51430215046235 |
oct | 7301671167053 |
9 | 1713717327048 |
10 | 507056025131 |
11 | 18604a9a8627 |
12 | 8233005388b |
13 | 38a79c3b686 |
14 | 1a7823a5255 |
15 | d2ca3173db |
hex | 760ee4ee2b |
507056025131 has 4 divisors (see below), whose sum is σ = 514001998152. Its totient is φ = 500110052112.
The previous prime is 507056025121. The next prime is 507056025143. The reversal of 507056025131 is 131520650705.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 507056025131 - 26 = 507056025067 is a prime.
It is a super-2 number, since 2×5070560251312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 507056025091 and 507056025100.
It is not an unprimeable number, because it can be changed into a prime (507056025121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3472986401 + ... + 3472986546.
It is an arithmetic number, because the mean of its divisors is an integer number (128500499538).
Almost surely, 2507056025131 is an apocalyptic number.
507056025131 is a deficient number, since it is larger than the sum of its proper divisors (6945973021).
507056025131 is an equidigital number, since it uses as much as digits as its factorization.
507056025131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6945973020.
The product of its (nonzero) digits is 31500, while the sum is 35.
Adding to 507056025131 its reverse (131520650705), we get a palindrome (638576675836).
The spelling of 507056025131 in words is "five hundred seven billion, fifty-six million, twenty-five thousand, one hundred thirty-one".
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