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50804814433 = 352914396377
BaseRepresentation
bin101111010100001100…
…111111001001100001
311212010200012222110211
4233110030333021201
51313022013030213
635201151254121
73445663540342
oct572414771141
9155120188424
1050804814433
111a600aa204a
129a1a51a341
134a3871a099
14265d5900c9
1514c536d53d
hexbd433f261

50804814433 has 4 divisors (see below), whose sum is σ = 50819214340. Its totient is φ = 50790414528.

The previous prime is 50804814427. The next prime is 50804814469. The reversal of 50804814433 is 33441840805.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2956314384 + 47848500049 = 54372^2 + 218743^2 .

It is a cyclic number.

It is not a de Polignac number, because 50804814433 - 229 = 50267943521 is a prime.

It is a super-2 number, since 2×508048144332 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (50804814133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7194660 + ... + 7201717.

It is an arithmetic number, because the mean of its divisors is an integer number (12704803585).

Almost surely, 250804814433 is an apocalyptic number.

It is an amenable number.

50804814433 is a deficient number, since it is larger than the sum of its proper divisors (14399907).

50804814433 is a wasteful number, since it uses less digits than its factorization.

50804814433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14399906.

The product of its (nonzero) digits is 184320, while the sum is 40.

The spelling of 50804814433 in words is "fifty billion, eight hundred four million, eight hundred fourteen thousand, four hundred thirty-three".

Divisors: 1 3529 14396377 50804814433