Base | Representation |
---|---|
bin | 100100111111001000101… |
… | …0000101100011011001011 |
3 | 122222222002201122220101121 |
4 | 1021332101100230123023 |
5 | 1131241232121240010 |
6 | 14451135111500111 |
7 | 1033155656554255 |
oct | 111762120543313 |
9 | 18888081586347 |
10 | 5083383383755 |
11 | 168a93a43a966 |
12 | 6a123a987637 |
13 | 2ab4901549b1 |
14 | 138073a04cd5 |
15 | 8c36cc643da |
hex | 49f9142c6cb |
5083383383755 has 4 divisors (see below), whose sum is σ = 6100060060512. Its totient is φ = 4066706707000.
The previous prime is 5083383383753. The next prime is 5083383383783. The reversal of 5083383383755 is 5573833833805.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 5083383383755 - 21 = 5083383383753 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5083383383693 and 5083383383702.
It is not an unprimeable number, because it can be changed into a prime (5083383383753) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 508338338371 + ... + 508338338380.
It is an arithmetic number, because the mean of its divisors is an integer number (1525015015128).
Almost surely, 25083383383755 is an apocalyptic number.
5083383383755 is a deficient number, since it is larger than the sum of its proper divisors (1016676676757).
5083383383755 is a wasteful number, since it uses less digits than its factorization.
5083383383755 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1016676676756.
The product of its (nonzero) digits is 108864000, while the sum is 61.
The spelling of 5083383383755 in words is "five trillion, eighty-three billion, three hundred eighty-three million, three hundred eighty-three thousand, seven hundred fifty-five".
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