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51001102035 = 345139686819
BaseRepresentation
bin101111011111111001…
…110000111011010011
311212122100120102110000
4233133321300323103
51313422240231120
635232442341043
73453566133402
oct573771607323
9155570512400
1051001102035
111a6a1879904
129a741ba783
134a6a2a46b0
14267b687639
1514d76e2990
hexbdfe70ed3

51001102035 has 40 divisors (see below), whose sum is σ = 98456838480. Its totient is φ = 25108232256.

The previous prime is 51001102007. The next prime is 51001102069. The reversal of 51001102035 is 53020110015.

It is not a de Polignac number, because 51001102035 - 29 = 51001101523 is a prime.

It is a super-2 number, since 2×510011020352 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 51001101999 and 51001102017.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 4838145 + ... + 4848674.

It is an arithmetic number, because the mean of its divisors is an integer number (2461420962).

Almost surely, 251001102035 is an apocalyptic number.

51001102035 is a deficient number, since it is larger than the sum of its proper divisors (47455736445).

51001102035 is a wasteful number, since it uses less digits than its factorization.

51001102035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9686849 (or 9686840 counting only the distinct ones).

The product of its (nonzero) digits is 150, while the sum is 18.

The spelling of 51001102035 in words is "fifty-one billion, one million, one hundred two thousand, thirty-five".

Divisors: 1 3 5 9 13 15 27 39 45 65 81 117 135 195 351 405 585 1053 1755 5265 9686819 29060457 48434095 87181371 125928647 145302285 261544113 377785941 435906855 629643235 784632339 1133357823 1307720565 1888929705 3400073469 3923161695 5666789115 10200220407 17000367345 51001102035