Base | Representation |
---|---|
bin | 101111100000001010… |
… | …100101100110110011 |
3 | 11212122122212110221022 |
4 | 233200022211212303 |
5 | 1313424402341430 |
6 | 35233121050055 |
7 | 3453651461645 |
oct | 574012454663 |
9 | 155578773838 |
10 | 51005512115 |
11 | 1a6a43111a8 |
12 | 9a7578692b |
13 | 4a6b189acc |
14 | 267c0b4895 |
15 | 14d7cb44e5 |
hex | be02a59b3 |
51005512115 has 4 divisors (see below), whose sum is σ = 61206614544. Its totient is φ = 40804409688.
The previous prime is 51005512087. The next prime is 51005512123. The reversal of 51005512115 is 51121550015.
51005512115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51005512115 - 220 = 51004463539 is a prime.
It is a super-2 number, since 2×510055121152 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5100551207 + ... + 5100551216.
It is an arithmetic number, because the mean of its divisors is an integer number (15301653636).
Almost surely, 251005512115 is an apocalyptic number.
51005512115 is a deficient number, since it is larger than the sum of its proper divisors (10201102429).
51005512115 is a wasteful number, since it uses less digits than its factorization.
51005512115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10201102428.
The product of its (nonzero) digits is 1250, while the sum is 26.
The spelling of 51005512115 in words is "fifty-one billion, five million, five hundred twelve thousand, one hundred fifteen".
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