Base | Representation |
---|---|
bin | 101111100000100000… |
… | …101100001101101001 |
3 | 11212200001202212010102 |
4 | 233200200230031221 |
5 | 1313432343300340 |
6 | 35233445155145 |
7 | 3454051643516 |
oct | 574040541551 |
9 | 155601685112 |
10 | 51011306345 |
11 | 1a6a760951a |
12 | 9a776bbab5 |
13 | 4a6c43824c |
14 | 267cb8230d |
15 | 14d855b215 |
hex | be082c369 |
51011306345 has 4 divisors (see below), whose sum is σ = 61213567620. Its totient is φ = 40809045072.
The previous prime is 51011306329. The next prime is 51011306347. The reversal of 51011306345 is 54360311015.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 28894560256 + 22116746089 = 169984^2 + 148717^2 .
It is a cyclic number.
It is not a de Polignac number, because 51011306345 - 24 = 51011306329 is a prime.
It is not an unprimeable number, because it can be changed into a prime (51011306347) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5101130630 + ... + 5101130639.
It is an arithmetic number, because the mean of its divisors is an integer number (15303391905).
Almost surely, 251011306345 is an apocalyptic number.
It is an amenable number.
51011306345 is a deficient number, since it is larger than the sum of its proper divisors (10202261275).
51011306345 is a wasteful number, since it uses less digits than its factorization.
51011306345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10202261274.
The product of its (nonzero) digits is 5400, while the sum is 29.
The spelling of 51011306345 in words is "fifty-one billion, eleven million, three hundred six thousand, three hundred forty-five".
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