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51013031513051 = 257198494286043
BaseRepresentation
bin10111001100101011001011…
…00111110100101111011011
320200121210112212200010212102
423212111211213310233123
523141244142031404201
6300255021350234015
713513366322254436
oct1346254547645733
9220553485603772
1051013031513051
1115288561422683
12587a80105590b
13226067b77508a
14c8508866081d
155d6e754a026b
hex2e65659f4bdb

51013031513051 has 4 divisors (see below), whose sum is σ = 51211525799352. Its totient is φ = 50814537226752.

The previous prime is 51013031513039. The next prime is 51013031513057. The reversal of 51013031513051 is 15031513031015.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51013031513051 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51013031513057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 99247142765 + ... + 99247143278.

It is an arithmetic number, because the mean of its divisors is an integer number (12802881449838).

Almost surely, 251013031513051 is an apocalyptic number.

51013031513051 is a deficient number, since it is larger than the sum of its proper divisors (198494286301).

51013031513051 is a wasteful number, since it uses less digits than its factorization.

51013031513051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 198494286300.

The product of its (nonzero) digits is 3375, while the sum is 29.

Adding to 51013031513051 its reverse (15031513031015), we get a palindrome (66044544544066).

The spelling of 51013031513051 in words is "fifty-one trillion, thirteen billion, thirty-one million, five hundred thirteen thousand, fifty-one".

Divisors: 1 257 198494286043 51013031513051