Base | Representation |
---|---|
bin | 101111100001000111… |
… | …110001110111101011 |
3 | 11212200210001110002000 |
4 | 233201013301313223 |
5 | 1313443004200011 |
6 | 35234452542043 |
7 | 3454235021523 |
oct | 574107616753 |
9 | 155623043060 |
10 | 51021553131 |
11 | 1a70237803a |
12 | 9a7b021923 |
13 | 4a715b5233 |
14 | 268028c683 |
15 | 14d93d2356 |
hex | be11f1deb |
51021553131 has 16 divisors (see below), whose sum is σ = 78873899520. Its totient is φ = 32535482760.
The previous prime is 51021553001. The next prime is 51021553153. The reversal of 51021553131 is 13135512015.
51021553131 is a `hidden beast` number, since 5 + 102 + 1 + 553 + 1 + 3 + 1 = 666.
It is not a de Polignac number, because 51021553131 - 211 = 51021551083 is a prime.
It is a super-2 number, since 2×510215531312 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 51021553095 and 51021553104.
It is not an unprimeable number, because it can be changed into a prime (51021553171) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 41079535 + ... + 41080776.
It is an arithmetic number, because the mean of its divisors is an integer number (4929618720).
Almost surely, 251021553131 is an apocalyptic number.
51021553131 is a deficient number, since it is larger than the sum of its proper divisors (27852346389).
51021553131 is a wasteful number, since it uses less digits than its factorization.
51021553131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82160343 (or 82160337 counting only the distinct ones).
The product of its (nonzero) digits is 2250, while the sum is 27.
The spelling of 51021553131 in words is "fifty-one billion, twenty-one million, five hundred fifty-three thousand, one hundred thirty-one".
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