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51023033121 = 344338392049
BaseRepresentation
bin101111100001001101…
…011011001100100001
311212200212211122020110
4233201031123030201
51313443344024441
635234544401533
73454253424414
oct574115331441
9155625748213
1051023033121
111a703198a75
129a7b6162a9
134a719b2a78
142680555b7b
1514d95c5b16
hexbe135b321

51023033121 has 8 divisors (see below), whose sum is σ = 68184280800. Its totient is φ = 33938570432.

The previous prime is 51023033111. The next prime is 51023033161. The reversal of 51023033121 is 12133032015.

51023033121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 51023033121 - 213 = 51023024929 is a prime.

It is not an unprimeable number, because it can be changed into a prime (51023033101) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19194696 + ... + 19197353.

It is an arithmetic number, because the mean of its divisors is an integer number (8523035100).

Almost surely, 251023033121 is an apocalyptic number.

It is an amenable number.

51023033121 is a deficient number, since it is larger than the sum of its proper divisors (17161247679).

51023033121 is a wasteful number, since it uses less digits than its factorization.

51023033121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38392495.

The product of its (nonzero) digits is 540, while the sum is 21.

Adding to 51023033121 its reverse (12133032015), we get a palindrome (63156065136).

The spelling of 51023033121 in words is "fifty-one billion, twenty-three million, thirty-three thousand, one hundred twenty-one".

Divisors: 1 3 443 1329 38392049 115176147 17007677707 51023033121