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51034040121 = 317011346707
BaseRepresentation
bin101111100001110111…
…011010011100111001
311212201122112212000010
4233201313122130321
51314004203240441
635240020332133
73454446116661
oct574167323471
9155648485003
1051034040121
111a709426769
129a83244049
134a74067a9c
142681bbd1a1
1514da54c116
hexbe1dda739

51034040121 has 4 divisors (see below), whose sum is σ = 68045386832. Its totient is φ = 34022693412.

The previous prime is 51034040111. The next prime is 51034040131. The reversal of 51034040121 is 12104043015.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (51034040111) and next prime (51034040131).

It is not a de Polignac number, because 51034040121 - 27 = 51034039993 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51034040111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8505673351 + ... + 8505673356.

It is an arithmetic number, because the mean of its divisors is an integer number (17011346708).

Almost surely, 251034040121 is an apocalyptic number.

It is an amenable number.

51034040121 is a deficient number, since it is larger than the sum of its proper divisors (17011346711).

51034040121 is a wasteful number, since it uses less digits than its factorization.

51034040121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17011346710.

The product of its (nonzero) digits is 480, while the sum is 21.

Adding to 51034040121 its reverse (12104043015), we get a palindrome (63138083136).

The spelling of 51034040121 in words is "fifty-one billion, thirty-four million, forty thousand, one hundred twenty-one".

Divisors: 1 3 17011346707 51034040121