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51045225113 = 59865173307
BaseRepresentation
bin101111100010100010…
…000101001010011001
311212202102121002221002
4233202202011022121
51314020034200423
635241100154345
73454643153201
oct574242051231
9155672532832
1051045225113
111a714776163
129a86b389b5
134a76482b1c
142683491401
1514db50b228
hexbe2885299

51045225113 has 4 divisors (see below), whose sum is σ = 51910398480. Its totient is φ = 50180051748.

The previous prime is 51045225103. The next prime is 51045225139. The reversal of 51045225113 is 31152254015.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51045225113 - 24 = 51045225097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51045225103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 432586595 + ... + 432586712.

It is an arithmetic number, because the mean of its divisors is an integer number (12977599620).

Almost surely, 251045225113 is an apocalyptic number.

It is an amenable number.

51045225113 is a deficient number, since it is larger than the sum of its proper divisors (865173367).

51045225113 is an equidigital number, since it uses as much as digits as its factorization.

51045225113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 865173366.

The product of its (nonzero) digits is 6000, while the sum is 29.

Adding to 51045225113 its reverse (31152254015), we get a palindrome (82197479128).

The spelling of 51045225113 in words is "fifty-one billion, forty-five million, two hundred twenty-five thousand, one hundred thirteen".

Divisors: 1 59 865173307 51045225113