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510485117147 = 2939173693473
BaseRepresentation
bin1110110110110110100…
…10001011100011011011
31210210122120210211222122
413123123102023203123
531330433142222042
61030302535411455
751611203621115
oct7333322134333
91723576724878
10510485117147
1118754a5a4175
1282b28523b8b
13391a54ac0c5
141a9c99863b5
15d42b3b97d2
hex76db48b8db

510485117147 has 4 divisors (see below), whose sum is σ = 510658813560. Its totient is φ = 510311420736.

The previous prime is 510485117101. The next prime is 510485117159. The reversal of 510485117147 is 741711584015.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 510485117147 - 28 = 510485116891 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 510485117098 and 510485117107.

It is not an unprimeable number, because it can be changed into a prime (510485117647) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86843798 + ... + 86849675.

It is an arithmetic number, because the mean of its divisors is an integer number (127664703390).

Almost surely, 2510485117147 is an apocalyptic number.

510485117147 is a deficient number, since it is larger than the sum of its proper divisors (173696413).

510485117147 is a wasteful number, since it uses less digits than its factorization.

510485117147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 173696412.

The product of its (nonzero) digits is 156800, while the sum is 44.

The spelling of 510485117147 in words is "five hundred ten billion, four hundred eighty-five million, one hundred seventeen thousand, one hundred forty-seven".

Divisors: 1 2939 173693473 510485117147