5104910576113 has 4 divisors (see below), whose sum is σ = 5105439976048. Its totient is φ = 5104381176180.

The previous prime is 5104910576093. The next prime is 5104910576119. The reversal of 5104910576113 is 3116750194015.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5104910576113 - 2²¹ = 5104908478961 is a prime.

It is a super-2 number, since 2×5104910576113² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 5104910576113.

It is not an unprimeable number, because it can be changed into a prime (5104910576119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 264685503 + ... + 264704788.

It is an arithmetic number, because the mean of its divisors is an integer number (1276359994012).

Almost surely, 2^{5104910576113} is an apocalyptic number.

It is an amenable number.

5104910576113 is a deficient number, since it is larger than the sum of its proper divisors (529399935).

5104910576113 is an equidigital number, since it uses as much as digits as its factorization.

5104910576113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 529399934.

The product of its (nonzero) digits is 113400, while the sum is 43.

The spelling of 5104910576113 in words is "five trillion, one hundred four billion, nine hundred ten million, five hundred seventy-six thousand, one hundred thirteen".